Python分治法解决最近对问题
class nearestPoint:
def __init__(self, aList):
self.aList = aList
def calculate(self):
if self.aList == None or len(self.aList) == 0:
return
if len(self.aList) == 1:
return 0
global xRangeList, yRangeList
xRangeList, yRangeList = self.Mergesort(self.aList, 0), self.Mergesort(self.aList, 1)
return self.ClosestPair(xRangeList, yRangeList)
def Mergesort(self, aList, axis):
if len(aList) <= 1:
return aList
pivot = len(aList)//2
leftArray = aList[:pivot]
rightArray = aList[pivot:]
return self.Merge(self.Mergesort(leftArray, axis), self.Mergesort(rightArray, axis), axis)
def Merge(self, leftList, rightList, axis):
output = []
leftIndex, rightIndex = 0, 0
while leftIndex < len(leftList) and rightIndex < len(rightList):
if leftList[leftIndex][axis] < rightList[rightIndex][axis]:
output.append(leftList[leftIndex])
leftIndex += 1
else:
output.append(rightList[rightIndex])
rightIndex += 1
while leftIndex < len(leftList):
output.append(leftList[leftIndex])
leftIndex += 1
while rightIndex < len(rightList):
output.append(rightList[rightIndex])
rightIndex += 1
return output
def ClosestPair(self, xList, yList):
if len(xList) == 2:
temp1 = ((xList[0][0]-xList[1][0])**2+(xList[0][1]-xList[1][1])**2)**0.5
temp2 = ((yList[0][0]-yList[1][0])**2+(yList[0][1]-yList[1][1])**2)**0.5
return min(temp1, temp2)
elif len(xList) == 3:
temp1 = min((xList[1][0] - xList[0][0])**2 + (xList[1][1] - xList[0][1])**2, (yList[1][0] - yList[0][0])**2 + (yList[1][1] - yList[0][1])**2)
temp2 = min((xList[2][0] - xList[0][0])**2 + (xList[2][1] - xList[0][1])**2, (yList[2][0] - yList[0][0])**2 + (yList[2][1] - yList[0][1])**2)
temp3 = min((xList[2][0] - xList[1][0])**2 + (xList[2][1] - xList[1][1])**2, (yList[2][0] - yList[1][0])**2 + (yList[2][1] - yList[1][1])**2)
temp = min(temp1, temp2)
return (min(temp, temp3))**0.5
else:
length = len(xList)
pivot = length//2
xLeft, xRight, yLeft, yRight = xList[:pivot], xList[pivot:], yList[:pivot], yList[pivot:]
d1, d2 = self.ClosestPair(xLeft, yLeft), self.ClosestPair(xRight, yRight)
d = min(d1, d2)
m = xList[pivot][0]
S = []
for i in range(len(yList)):
if abs(yList[i][0] - m) < d:
S.append(yList[i])
dminsq = d**2
if len(S) > 2:
for i in range(len(S)-1):
k = i + 1
while k <= len(S) - 1 and (S[k][1] - S[i][1])**2 < dminsq:
dminsq = min((S[k][0]-S[i][0])**2+(S[k][1]-S[i][1])**2, dminsq)
k += 1
elif len(S) == 2:
dminsq = min((S[1][0]-S[0][0])**2+(S[1][1]-S[0][1])**2, dminsq)
return dminsq**0.5
A = [[3.7,2.7],[6.9,10.2],[10.5,6.3],[2.0,5.2],[7.6,9.6],[6.4,6.8],[8.9,6.3],[4.8,9.9],[3.1,6.1],[5.3,5.8],[3.6,8.1],[2.9,3.7],[3.2,4.1],[4.7,3.9]]
s = nearestPoint(A)
print(s.calculate())
解压密码: detechn或detechn.com
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