Python二叉树中和为某一值的路径

递归

'''
输入一颗二叉树和一个整数，打印出二叉树中结点值的和为输入整数的所有路径。
路径定义为从树的根结点开始往下一直到叶结点所经过的结点形成一条路径。
'''
# -*- coding:utf-8 -*-
class TreeNode:
    def __init__(self, x):
        self.val = x
        self.left = None
        self.right = None
class Solution:
    # 返回二维列表，内部每个列表表示找到的路径
    def FindPath(self, root, sum):
        if not root:
            return []
        if root.left == None and root.right == None:
            if sum == root.val:
                return [[root.val]]
            else:
                return []
        stack = []
        leftStack = self.pathSum(root.left, sum - root.val)
        for i in leftStack:
            i.insert(0, root.val)
            stack.append(i)
        rightStack = self.pathSum(root.right, sum - root.val)
        for i in rightStack:
            i.insert(0, root.val)
            stack.append(i)
        return stack

    # 优化写法
    def pathSum(self, root, sum):
        if not root: return []
        if root.left == None and root.right == None:
            if sum == root.val:
                return [[root.val]]
            else:
                return []
        a = self.pathSum(root.left, sum - root.val) + self.pathSum(root.right, sum - root.val)
        return [[root.val] + i for i in a]

pNode1 = TreeNode(10)
pNode2 = TreeNode(5)
pNode3 = TreeNode(12)
pNode4 = TreeNode(4)
pNode5 = TreeNode(7)


pNode1.left = pNode2
pNode1.right = pNode3
pNode2.left = pNode4
pNode2.right = pNode5


S = Solution()
print(S.FindPath(pNode1, 22))
# 测试用例：[1,-2,-3,1,3,-2,null,-1]  -1
# 测试用例：[-2, None, -3] -5